This is a list: [x, y]. Tuple and List. There are no duplicates allowed. The reason you’re getting the unhashable type: 'list' exception is because k = list[0:j] sets k to be a “slice” of the list, which is logically another, often shorter, list. Unlike sequences, which are indexed by a range of numbers, dictionaries are indexed by keys, which can be any immutable type; strings and numbers can always be keys. TypeError: unhashable type: 'list' when using built-in set function , Sets require their items to be hashable. Solved: Original User: MCline19 For the following code, lines 79 & 97: I am trying to send emails to multiple addresses. Conversely, you can also do. If you want to unpack the sets, maybe import itertools and then you can print(max(list(itertools.chain.from_iterable(dict1.values())),key=dict2.get)) I had to comment the last part out because I managed to make it not work at all. I want to get the count of words based on those users which are named as gold_users. Dictionaries do not have any index numbers and so this syntax does not apply. TypeError: unhashable type: 'list' bij gebruik van de ingebouwde set-functie. Python: TypeError: unhashable type: 'list', TypeError: unhashable type: 'list' usually means that you are trying to use a list as an hash argument. So your program is trying to find the value of the set itself, and that's not possible. TypeError: unhashable type: 'list' You can resolve this issue by casting list to tuple . I have a dict (IDMapping) that I'm looking up to in order to get a value, which I am then using to lookup to another dict ... You can create a set holding the different IDs and then compare the size of that set to the total number of quests. Now, we write a for loop that goes through our list of cakes and finds the ones that have been sold more than five times. What you need is to get just the first item in list, written like so k = list[0]. pandas dataframe: df.shape (86, 245) However, when I do this: df[0, :] I get the error: *** TypeError: unhashable type How do I fix this? Those cakes will be added to the “sold_more_than_five” dictionary: But I am receiving this error: Runtime Lists are created using square brackets: unhashable type list python. Contact Information #3940 Sector 23, Gurgaon, Haryana (India) Pin :- 122015. contact@stechies.com -- New Otherwise first a list from the set is created in memory, then it's applied to the dataframe. Dictionaries cannot be sliced like a list. eg: [[1,2,3,4],[4,5,6,7]] Als ik de ingebouwde set-functie gebruik om duplicaten uit deze lijst te verwijderen, krijg ik de foutmelding. Just note that the order of the elements in a list is generally lost when converting the list to a set since a set is inherently unordered. [[(a,b) for a in range(3)] for b in range(3)] is een lijst. Pandas Typeerror: Unhashable Type: 'list' A pilot's messages Is it legal check my site Not the answer it doesn't explicitly talk about mutable objects that compare by identity. The list is an unhashable object. By specifying a colon and an index value, you are telling Python which objects to retrieve. TypeError: unhashable type: 'list' De code die ik gebruik is. Hoe komt het dat de ene werkt (lijst) en de andere niet (ingesteld)? my_list = list(my_set) or, for Python 3, my_list = [*my_set] to create a list from a set. 2. python提示：TypeError: unhashable type: 'list' Enter. set cheat sheet type set use Used for storing immutable data types uniquely. This was before the holidays. The reason you’re getting the unhashable type: 'list' exception is because k = list[0:j] sets k to be a “slice” of the list, which is another, usually shorter, list. ” dictionary: typeerror unhashable type: 'list set to list unhashable type: 'list ' you can resolve issue. 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